There is not much point to further discussion, because I just keep repeating
myself.  The case you are discussing is partially valid where the shield
material is large relative to a wavelength, and it is reflecting an
electromagnetic field.  The currents induced in this case are due to the
electric field vector, according to J = sigma E.  But even here, without an
adequate shield termination the currents induced to flow on the inside of
the shield will escape to the outside and re-radiate.

If the shielding is specifically for the low frequency magnetic component of
the field then the eddy currents flow due to Faraday Law induction, which is
a vector phenomenon, and then the shield has to form a loop penetrated by
the magnetic field vector, or it won't work.

> From: "Robert A. Macy" <[email protected]>
> Date: Thu, 15 Sep 2005 15:27:54 -0700
> To: Ken Javor <[email protected]>
> Cc: [email protected]
> Subject: Re: When is a cable shield not a cable shield?
> 
> Eddy currents exist everywhere the conductor looks like a
> shorted turn on a transformer.
> 
> Imagine a perfectly balanced pair of wires, driven in a
> perfetly balanced manner. A wire down, a wire back - a
> loop.  That pair will radiate right out through its loop.
> A simple plate of conductor placed over the loop will get
> eddy currents generated in it that "cancels" to lower
> radiation.  
> 
> The plate does not have to be terminated to have this
> effect.  Simply covering the surface of the loop is
> sufficient.  Plus with the wires perfectly balanced and the
> drive pervectly balanced there will be no residual signal
> put upon the plate, so the plate does not radiate, or
> reradiate.  
> 
> - Robert -
> 
> On Thu, 15 Sep 2005 14:41:56 -0500
> Ken Javor <[email protected]> wrote:
>> See response to Mr. Woodgate.  Shorted fibers are not an
>> issue, my argument
>> holds if the shield material is a solid copper pipe.  You
>> won't get eddy
>> currents flowing in that pipe until the ends are
>> terminated so currents can
>> flow in a loop.  The magnetic vector flows around the
>> circumference of the
>> pipe, but that is not the path the eddy currents nee to
>> take.  They must
>> flow longitudinally down the pipe.  The cable becomes the
>> center of a
>> coaxial transmission line; the shield is the coaxial
>> transmission line
>> shield and return conductor.
>> 
>>> From: "Robert A. Macy" <[email protected]>
>>> Date: Thu, 15 Sep 2005 11:28:26 -0700
>>> To: Ken Javor <[email protected]>
>>> Cc: [email protected]
>>> Subject: Re: When is a cable shield not a cable shield?
>>> 
>>> Yes, it can.
>>> 
>>> The fibres are all shorted out making it a pseudo-metal
>>> plane. 
>>> 
>>> Plus, the loops of interest are pretty much contained
>> in
>>> between the two ends of the shield.
>>> 
>>> To see how much effect there is measure the inductance
>> of
>>> the loop inside shield and ouside the loop.
>>> 
>>> - Robert -
>>> 
>>> On Thu, 15 Sep 2005 11:50:33 -0500
>>> Ken Javor <[email protected]> wrote:
>>>> I have a problem with this as well.  A non-magnetic
>>>> shield material protects
>>>> against magnetic field radiation by providing a path
>> for
>>>> eddy currents to
>>>> flow in.  The eddy currents flow in such a way as to
>>>> cause a magnetic field
>>>> that opposes the originating field (Lenz' law).  In
>> order
>>>> for the eddy
>>>> currents to have sufficient magnitude to cause field
>>>> cancellation, the
>>>> shield must provide a very low impedance short
>> circuit.
>>>> An open-circuited
>>>> shield braid cannot perform this function.
>>>> 
>>>>> From: "Robert A. Macy" <[email protected]>
>>>>> Date: Thu, 15 Sep 2005 09:16:09 -0700
>>>>> To: "Hudson, Alan" <[email protected]>
>>>>> Cc: [email protected]
>>>>> Subject: Re: When is a cable shield not a cable
>> shield?
>>>>> 
>>>>> Alan,
>>>>> 
>>>>> Think also in terms of magnetic fields, or "area
>>>> loops".
>>>>> 
>>>>> The area defined by the small loop between signal
>> lines
>>>> and
>>>>> ground lines now have rather opaque metal plates over
>>>> them.
>>>>> Starting around 10KHz the conductive "shield" kills
>> all
>>>>> the magnetic fields coming out.  Which were probably
>>>> more
>>>>> significant than the E-Field contributions.
>>>>> 
>>>>> - Robert -
>>>>> 
>>>>> On Thu, 15 Sep 2005 16:22:31 +0100
>>>>> "Hudson, Alan" <[email protected]> wrote:
>>>>>> G'Day!
>>>>>> 
>>>>>> Came across an oddity today which has failed to
>>>> stimulate
>>>>>> any memories (from
>>>>>> about the time the old King died!) of basic
>>>>>> electromagnetic theory. A
>>>>>> well-known computer Company supplies what it calls
>>>>>> "shielded ribbon cables".
>>>>>> When we examine one of these we find it's
>> essentially
>>>> a
>>>>>> metallic braid
>>>>>> sleeve around a standard ribbon cable. The braid
>> isn't
>>>>>> connected to anything
>>>>>> (not even a drain wire at the connector ends).
>>>>>> 
>>>>>> So what level of shielding is this going to give -
>> if
>>>>>> any?
>>>>>> 
>>>>>> I could imagine signal lines being capacitively
>>>> coupled
>>>>>> to the braid and
>>>>>> then capacitively coupled to any 0V lines in the
>>>> ribbon.
>>>>>> But I can also
>>>>>> imagine signal lines being capacitively coupled to
>>>> other
>>>>>> signal lines.
>>>>>> Similarly with external signals hitting the braid -
>>>> they
>>>>>> could go to either
>>>>>> the signal or 0V lines - yes/no?
>>>>>> 
>>>>>> I know I should know the answer to this, but
>>>> obviously,
>>>>>> today at least, if I
>>>>>> had a brain I'd be dangerous!
>>>>>> 
>>>>>> :-)
>>>>>> 
>>>>>> Regards,
>>>>>> 
>>>>>> Alan
>>>>>> -- 
>>>>>> Principal Engineer,
>>>>>> BAE Systems Limited,
>>>>>> UK
>>>>> 
>>>>> -
>>>>> 2005 IEEE Symposium on Product Safety Engineering
>>>>> 3-4 October   Schaumburg, IL
>>>>> http://www.ieee-pses.org/symposium
>>>>> 
> 

-
   2005 IEEE Symposium on Product Safety Engineering
             3-4 October   Schaumburg, IL
          http://www.ieee-pses.org/symposium


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