I agree with John - it is necessary to know what purpose the question is
asked, or the purpose to which the answer is to be put!

In EMC I mostly want to know that the emission wave front is close to 377 Ohms
- as this is (supposed to be) the impedance at which the "antenna" calibration
is made. My Don White gives the distance to this "impedance" boundary as
lamda/(2.Pi) - this is where the wave impedance is within 10% or so of 377
Ohms.

There is a constraint, in that the above equation is for an isotropic radiator
- that is unity gain. If lambda is multiplied by the (numeric) gain of the
antenna and then divided by 2Pi this gives a better approximation to the
impedance boundary for antennas with gain.

I hope that this helps.

Tim


From: [email protected] [mailto:[email protected]] On Behalf Of John Woodgate
Sent: 02 August 2006 08:59
To: [email protected]
Subject: Re: Near field/Far field what is D.

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In message <001c01c6b604$c0ed2810$6401a8c0@homepc>, dated Wed, 2 Aug 2006,
Iain Summers <[email protected]> writes
>There are various references and opinions as to what constitutes the
>near field far field boundary. The common one from antenna theory is
>2D^2/lambda where D is defined as the largest aperture of the antenna.

There isn't a sharp boundary. What you take as the boundary depends on why you
want to know where it is, and you don't tell us that.

For example, you might decide that you want to know where the phase angle
between E and H is only 1 degree. Or is 45 degrees. Or more.
> 
>Has anyone researched what the limitations of this formula are? I am
>interested in the far field boundary between 1-30MHz for large loops of
>wire.

Large compared with the wavelength at 1 MHz? That's large indeed!

>In terms of a loop if this formula is applicable is D the circumference
>or diameter of the loop.

Or maybe the area?
--
OOO - Own Opinions Only. Try www.jmwa.demon.co.uk and www.isce.org.uk
2006 is YMMVI- Your mileage may vary immensely.

John Woodgate, J M Woodgate and Associates, Rayleigh, Essex UK

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