Guys,

What Don says is correct; but I don't know if it directly hits where the
confusion comes from.

I think that this is the confusion.

The inductor is modeled as an ideal inductance in series with its
Equivalent Series Resistor (ESR).

The voltage across the ideal inductor is Vind=L*(di/dt)...this voltage can
be very high, if the rate of change of current is high.  This voltage is
zero for a DC circuit

The voltage across the ESR is simply Vesr= I*Resr...They are using rms
values; so they're saying that Vrms = Irms (Resr).  This voltage is
non-zero whenever any type of current flows through the inductor.

The total voltage across the inductor is Vind + Vesr

The power dissipated in the inductor is Pind + Pesr.  The Pind term is
usually purely reactive (no heat); however, there are core heating effects
which I'll mention later.

The current limit (on the spec sheet) of the inductor usually has more to
do with the saturation limits of the core...i.e., the core will saturate
at currents above the specified current limit...than with the power
dissipation of the inductor.

Sometimes, you have to worry about whether you are saturating the
inductor...that's where you look at the specified current.

Sometimes you have to worry about whether you are overheating the
inductor...that's where you look at ESR and calcuate Irms...although the
spec sheet that started this thread seemed to specify a Vrms...that's OK,
but you have to realize that it's just the voltage across the ESR...not
the voltage across the whole inductor "model" which is the ESR and an
ideal inductor.

As far as peak voltage (based on L*(di/dt)...that's usually a problem for
parts around the inductor.  The inductor itself won't breakdown until the
voltage is so great so as to breakdown the insulation between the
windings...however, usually some other component in the circuit that's
connected in parallel with the inductor will breakdown first.   An example
of this is a snubber circuit in a flyback power supply.  Without the
snubber, the voltage on the primary winding (an a form of inductor) will
go through the roof during the flyback phase.  The primary winding will be
fine with that...but every FET, diode and cap connected to it would blow
to bits...if you didn't put a snubber on the circuit.

You can also overheat the core of an inductor by generating eddy currents
and other heat generating phenomena within the core itself...This is
usually proportional to the area within the B-H curve that you would draw
for your operating conditions.

For a good design, you would have to ensure that you are within the
boundaries under all four conditions...
1...staying within the power dissipation limits through the ESR this is
usually listed in Watts...... although it could be given as an rms current
limit or rms voltage limit...with both assumed to be across the ESR.
2....staying within the peak AC voltage limits so as to not blow up parts
around the inductor or breakdown the insulation of the inductor itself
3.... keeping the inductor out of saturation.
4....ensuring that you don't overheat the core due to B-H effects (I've
never seen this to be a problem for power supply or filter
circuits...mostly for AC power transformers)  For most inductors, you've
satisfied this if you just stay out of saturation.


The usage of the inductor (filter, power supply ...) usually dictates that
one of these limits will be bumped into first.

To directly answer the original question, they were specifying only the
voltage drop across the ESR...not the voltage across the "ideal inductor"
part of the inductor model.  It's part of the picture; but not the whole
picture.

So, if you wanted to use this inductor in a filter...the peak voltage
across the whole inductor could indeed exceed the voltage drop across the
ESR that was specified.

Just check all four conditions listed above; and see if you're OK.

I hope this helps.

Chris Maxwell, M.Sc
Electrical Engineer
Critical Imaging LLC

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