Hi Bob: 

You wrote: 
> You are correct about the inrush requirement.  It does not have to 
> be more than 500A for the voltages mentioned, but it also does not 
> have to be more than the margin required above the actual EUT inrush
> current. 

In IEC61000-4-11:2004, information about testing the AC source for peak
current capability was moved from clause 6.1.2 to clause 6.1.1.  See page 27,
in the paragraph starting "When it is believed that a generator . . . ".   
The amount of margin in the paragraph hasn't changed.  It still says the EUT
inrush must be less than 70% of the generator capability.  Sorry, my in-line
arithmetic was probably confusing. 

Pat Lawler
EMC Engineer
SL Power Electronics Corp.

[email protected] wrote on 05/20/2008 04:04:56 PM:
> I'm looking at edition 2, dated 2004-03, and it appears the wording 
> has not changed.
> 
> You are correct about the inrush requirement.  It does not have to 
> be more than 500A for the voltages mentioned, but it also does not 
> have to be more than the margin required above the actual EUT inrush
> current. We don't, at the present time, have the required fixture 
> (rectifier and capacitor)necessary to measure the output of the 
> power supply. I'm sure we can build it, but does anyone know of a source?
> 
> Thanks,
> Bob Richards, NCT

 
> --- On Tue, 5/20/08, [email protected] <[email protected]> wrote:
> > From: [email protected] <[email protected]>
> > Subject: Re: 61000-4-11 Inrush current
> > To: [email protected], [email protected]
> > Date: Tuesday, May 20, 2008, 3:00 PM
> > Hi Bob:
> >
> > I have a copy of IEC61000-4-11:1994.  Take another look at
> > clause 6.1.1.
> > It says the peak inrush current drive capability '...
> > need not exceed 500A
> > for 220V-240V mains,  or 250A for 100V-120V mains.'
> >
> > For a minimum capability, look at clause 6.2.2.  It says
> > that 'the
> > measured EUT peak inrush current shall be less than 70% of
> > the peak
> > current drive capability of the generator, ...'
> >      Ipk.EUT  <  70% * Ipk.generator
> > Solving for Ipk.generator gives:
> >      Ipk.EUT * 143%  <  Ipk.generator
> > Note the special test conditions for measuring the EUT peak
> > inrush current in Annex A.
> >
> > So your generator needs to be capable of a peak current
> > between  Ipk.EUT * 143%  and 500A.
> >
> > As far as your 'AC fault' information is concerned,
> > ask your associate
> > where it is documented.
> >
> > Pat Lawler
> > EMC Engineer
> > SL Power Electronics Corp.
> >
> > [email protected] wrote on 05/20/2008 05:11:26 AM:
> > > A question came up recently where I work about the
> > current
> > > requirements of the AC source used for testing voltage
> > dips and
> > > interrupts. I was told the scope of the standard is
> > for products up
> > > to 16A and that *includes* inrush current during
> > turn-on.
> >
> > > I referenced table 6.1.1 where the peak inrush current
> > capability
> > > must be 500A for 200 - 240v mains voltage, but was
> > told this table
> > > only covers AC fault conditions, not normal operations
> > (including
> > turn-on).
> >
> > > Since one of the tests is a >95% interruption for 5
> > seconds, would
> > > this be considered an AC fault, or a normal turn-on
> > for the EUT?
> > > Appendix A sure makes it sound like the inrush
> > requirement is for
> > > the power-up of the EUT.

> -
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