In message <[email protected]>, dated Sat, 13 Dec 2008, Gert Gremmen <[email protected]> writes:
>the two capacitances (+ wire and - wire) are inverse, you will need to >know the difference between the tow caps and use that cor the CM >current. If both capacitances are equal, the CM current will be >essentially zero. So why not add a small capacitor so as to *make* the capacitances equal? Adjust for minimum CM emission. Remember, you read it here first! (;-) -- OOO - Own Opinions Only. Try www.jmwa.demon.co.uk and www.isce.org.uk All these closing-downs have been caused by dozing clowns John Woodgate, J M Woodgate and Associates, Rayleigh, Essex UK - This message is from the IEEE Product Safety Engineering Society emc-pstc discussion list. To post a message to the list, send your e-mail to <[email protected]> All emc-pstc postings are archived and searchable on the web at: http://www.ieeecommunities.org/emc-pstc Graphics (in well-used formats), large files, etc. can be posted to that URL. Website: http://www.ieee-pses.org/ Instructions: http://listserv.ieee.org/request/user-guide.html List rules: http://www.ieee-pses.org/listrules.html For help, send mail to the list administrators: Scott Douglas <[email protected]> Mike Cantwell <[email protected]> For policy questions, send mail to: Jim Bacher: <[email protected]> David Heald: <[email protected]>
