For years I have understood that the Gain and Antenna factor are related by
the following equation:
 
AF=20 log (F[GHz])-G[isotropic]+30.3
 
And the E field (dBV/m) is given by
 
E=P[dBW.ant]+G+14.77: this equation is for 1m separation. P[dBW.ant] is the
power at the antenna. If 1m is actually in the far field of the antenna, then
it is possible to extend this equation by adding a term of [-20log(1/D) where
D is the distance in metres. 
 
There is some myth that the power at the antenna is the forward power minus
the reflected power. The gain / antenna factor measurement includes the
mismatch and when using the gain to calculate the field, the mismatch is
therefore accommodated automatically.
 
Regards
Tim
 
PS I have some proofs in MathCad somewhere if anyone wants to take a look.
Tim
 

************************

Tim Haynes 

Electromagnetic Engineering Specialist

SELEX Galileo, A Finmeccanica Company

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Luton

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(Phone () +44 (0) 1582 886239 (Mob )) +44 (0) 7540629920 (Fax  7)+44 (0)1582
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________________________________

From: Rodrigo Rodriguez [mailto:[email protected]] 
Sent: 12 May 2010 17:36
To: [email protected]
Subject: [PSES] Antenna TAF calculated from AF


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      Keep this in mind if you answer this message.
 
Hello all,
I would appreciate your comments/guidance about this question.
 
I have a calibrated biconical antenna and its calibration report includes its
AF (antenna factor) and the Gain at 1 meter.
 
I would like to get the corresponding TAF (Transmit Antenna Factor) for this
antenna at 1 m, 3 m and 10 m. 
 
The question is, Is it possible calculate TAF for distances at 1 m, 3 m & 10 m
using the AF at 1 m?
 
It may be a different situation for the 1 m as I already have the AF at that
distance. Do I need to get the calibrated AF for the other two distances?
 
Thank you very much.
 
Rodrigo Rodriguez

 


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