Kirk-

How are you simulating the input in the office?

Javid

----- Original Message ----- 
From: "Kirk Wallace" <[EMAIL PROTECTED]>
To: "Enhanced Machine Controller (EMC)" <emc-users@lists.sourceforge.net>
Sent: Monday, January 21, 2008 9:29 PM
Subject: [Emc-users] Serial ADC Shifting


>I have the a serial ADC setup and mostly working, but I have a problem
> with the output value being too high. I shift bit 11 through 0 into a
> byte as shown below.
>
> Full file here:
> http://www.wallacecompany.com/machine_shop/EMC2/serial_adc/LTC1286.comp
>
> ...
> case 1:                     // ***  Mode 1 : Shift Data from ADC
>  clock_out=0x1 & adc_step; // Set clock_out high on odd adc_step's
>    if (clock_out) {        // If clock_out is high ...
>      bit_shifted=(bit_in << which_bit);
>      accum=accum+bit_shifted;    // get input bit, shift to current bit
> location, and add to accumulator
>      which_bit--;
>    }
> ...
>
> On the shop PC the output comes out seven shifts too high. My office PC
> works properly. They both have the same software and EMC 2.2.2 and get
> undated automatically. I have a screen-shot showing the value of each
> shift on the bottom trace here:
>
> http://www.wallacecompany.com/machine_shop/EMC2/serial_adc/bad_shift-1a.png
>
> The first peak should have a value of 2048, but 262144 is indicated.
> Just before this shot, I looked at a trace of the shift values, and
> they were correct at 11 decrementing to 0.
>
> Both PC's are the same except, the office PC has a simulated input, and 
> the
> shop PC has the real ADC input.
>
> Anyone have any ideas how an unsigned integer can be seven bits off?
>
>
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