Greetings everybody; As I read the machinists hand book, tapers such as this mean the "included" angle, not the angle of just one side of a cone.
So, I've read, where I don't recall, that a taper lock hub is 7 degrees of taper. It doesn't self eject, but also does not need a lot of jacking force to unlock it. Or is that magic angle different, not 7 degrees? The sin(7)=0.121869343405147462, which I interpret as meaning if the tool travels an inch, the diameter change is 0.121869343405147462. But the tool is moving only .735" from one end of the taper to the other, so the additive value for the big end of the taper is then .735*0.121869343405147462=0.0895739674027833847. Since that is better than angstrom accuracy, round it down to 4 or 5 digits right of the decimal makes sense since I'm not carving a new Hubble mirror here. So, bore is .876" (I overshot 7/8" a red one) and I'd like the taper hub wall to be about 1/16" thick at the small end=1.0000". Then the diameter at the flange, .735" to the left of that 1" point, would 1.08957". Correct? Thanks. I might get this taper thing understood yet. Cheers, Gene Heskett -- "There are four boxes to be used in defense of liberty: soap, ballot, jury, and ammo. Please use in that order." -Ed Howdershelt (Author) Genes Web page <http://geneslinuxbox.net:6309/gene> ------------------------------------------------------------------------------ Check out the vibrant tech community on one of the world's most engaging tech sites, Slashdot.org! http://sdm.link/slashdot _______________________________________________ Emc-users mailing list Emc-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/emc-users
