Yes but for small angles sin() and tan() are almost identical. Sin(7)=0.1219
and tan(7)=0.1228

> -----Original Message-----
> From: Marcus Bowman [mailto:marcus.bow...@visible.eclipse.co.uk]
> Sent: Sunday, March 26, 2017 3:53 PM
> To: Enhanced Machine Controller (EMC)
> Subject: Re: [Emc-users] Making taper lock hubs
>
> Is the tangent of the angle not more useful? That uses the straight length
> instead of the hypotenuse (along the tapered face).
> Opposite over adjacent, rather than opposite over hypotenuse.
>
> Marcus
>
>
> On 26 Mar 2017, at 19:48, Gene Heskett wrote:
>
> > Greetings everybody;
> >
> > As I read the machinists hand book, tapers such as this mean the
> > "included" angle, not the angle of just one side of a cone.
> >
> > So, I've read, where I don't recall, that a taper lock hub is 7
> > degrees of taper. It doesn't self eject, but also does not need a lot
> > of jacking force to unlock it.  Or is that magic angle different, not 7
degrees?
> >
> > The sin(7)=0.121869343405147462, which I interpret as meaning if the
> > tool travels an inch, the diameter change is 0.121869343405147462.
> >
> > But the tool is moving only .735" from one end of the taper to the
> > other, so the additive value for the big end of the taper is then
> > .735*0.121869343405147462=0.0895739674027833847.  Since that is better
> > than angstrom accuracy, round it down to 4 or 5 digits right of the
> > decimal makes sense since I'm not carving a new Hubble mirror here.
> >
> > So, bore is .876" (I overshot 7/8" a red one) and I'd like the taper
> > hub wall to be about 1/16" thick at the small end=1.0000". Then the
> > diameter at the flange, .735" to the left of that 1" point, would
> > 1.08957".
> >
> > Correct?
> >
> > Thanks. I might get this taper thing understood yet.
> >
> > Cheers, Gene Heskett
> > --
> > "There are four boxes to be used in defense of liberty:
> > soap, ballot, jury, and ammo. Please use in that order."
> > -Ed Howdershelt (Author)
> > Genes Web page <http://geneslinuxbox.net:6309/gene>
> >
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