On 07/21/2020 04:07 AM, andy pugh wrote:
On Tue, 21 Jul 2020 at 05:52, Tom Smart <smart_tow...@hotmail.com> wrote:
If i keep the amps at the rating of 9.1 I should keep my 31.3 IN-LBS or 2.6
FT-LBS?
So 2.6 / .0813 would be 81.76 lbs of linear force?
So if my table weighs 200lbs my acceleration would be .41 G?
I'm wondering if I've done a calculation wrong
The way I think about it.[1]
Imagine pushing with a force of 1 lb on the end of a 1 foot handle
fastened to the end of the screw through one complete turn. That is
circle of radius 1 foot and a distance of 2 x pi X 12 = 75 inches and
a torque of 1 lb/ft
The screw moves 0.2 in
The ratio is 75" / .2" = 377:1
So 2.6 lbft on a 5tpi screw is 750lbs.
I think there was a feet to inches error in the calculation above. And
a shuffling of 0.0138 to 0.0813.
OK, I screwed up. I had to do a whole page of calculations
to see it. My cheat sheet was in INCH Pounds,
not FOOT pounds!
So, to start over :
31.3 Inch-Lb / 0.0318 = 985 Lbs linear force. That should
be fine.
Sorry for the error in my earlier posts.
Jon
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