Jupiter, didn't you watch Men In Black?

Join me in the Eastern Native Tree Society at http://www.nativetreesociety.org
and in the Primal Forests - Ancient Trees Community at:  
http://primalforests.ning.com/ 

  ----- Original Message ----- 
  From: Steve Galehouse 
  To: [email protected] 
  Sent: Friday, October 03, 2008 11:27 PM
  Subject: [ENTS] Re: Measurement methodology question


  Ed-

  Thanks, as a sociology major I'm utterly baffled by any math  procedures, but 
at least plant i.d. comes real easy, though I'm not sure why. I'll 
apprehend(confiscate) one of my kid's old calculators that gives a sine 
function.

  Pop quiz: Where was Elvis Presley born?(Genus and species required)

  Steve


  On Fri, Oct 3, 2008 at 10:47 PM, Edward Frank <[EMAIL PROTECTED]> wrote:

    Steve,

    No it is not the same.  The % scale is designed to convert a measured 
horizontal distance to a calculated height.  It is the tangent of the angle 
measured.  When you use the rangefinder you are not measuring the horizontal 
distance to the tree but the direct distance from your eye to the measuring 
point.   That is the hypotenuse of a right triangle.  You need to use the sin 
function to convert the measured distance to a height above level of the 
measurement.  So the % scale has no direct relationship to what you are 
measuring.

    Ed

    Join me in the Eastern Native Tree Society at 
http://www.nativetreesociety.org
    and in the Primal Forests - Ancient Trees Community at:  
http://primalforests.ning.com/ 

      ----- Original Message ----- 
      From: Steve G 
      To: ENTSTrees 
      Sent: Friday, October 03, 2008 10:35 PM
      Subject: [ENTS] Measurement methodology question



      ENTS

      I've just acquired a clinometer with both degree and percent scales. I
      understand the sine method of measuring with clinometer and laser
      rangefinder(at least I think I understand). Can I simplify an accurate
      measurement by taking rangefinder distance times % slope of
      clinometer, without translating a degree reading to a sine value?
      Intuitively it seems it should get to get to the same figure from
      different directions.--is this correct?

      Steve 





  


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