Randall Clague wrote:
> OK - this matches both my observations and my intuition.  But, I don't
> see why this is so.  Mathematically, it seems to me that a gravity
> turn is independent of whether the vehicle is under power; and that ,
> second for second, the trajectory will look the same, powered or not.
> What is different is the proportion of the flight that is powered.
> 
> Can someone resolve this paradox?

Imagine an aerodynamically-stabilized unguided rocket 
that tends to align its airframe with the direction of 
its airspeed. Its thrust is always aligned with its 
airframe (i.e., the engine has no gimbals or other 
means of deflecting its thrust off axis).

If we launch this rocket perfectly vertically and it 
stays vertical in flight, the thrust is always pushing 
upward. In this case there would be no directional 
difference between a long or short burn.

Now, assume that at some point during the ascent, 
the rocket is deflected so that its airframe is no 
longer perfectly vertical. If this happens during 
powered flight, the thrust produced after that moment 
will not be in the same (i.e., vertical) direction
as the initial thrust: it will tend to push the rocket 
sideways (relative to the vertical path) as well as 
upward, and its velocity will therefore come to have 
a horizontal component. The rocket, being aerodynamically 
stabilized, will tend to align itself with this new 
direction of motion, so its subsequent thrust will 
continue to accelerate it sideways as well as vertically. 
If the deflection happened in vertical coasting flight, 
there would be no "sideways" thrust, and the path would 
not be deflected.

Next, consider a rocket launched at an angle (or one that 
begins to deviate from vertical in flight, as in the prior 
example). Gravity will be pulling it sideways (relative to 
its path) instead of merely opposing the thrust. Again, we 
have a change of the direction of its path, and thus a change 
in the direction of its thrust. (This will cause the flight 
path to continue to increase its angle from vertical.)

>From this, we can deduce that the trajectory will depend on 
the thrust-time history as well as the initial launch angle - 
and (other factors being equal) the path of a long-burning 
rocket will be more influenced by differences in the initial 
launch angle (or by other perturbations, such as wind-deflection) 
than will that of a short-burning one.

-dave w
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