On Fri, 2003-10-03 at 22:45, David Masten wrote: > Dang nab it, now I have to go write out the equations and figure it out. > (Again!!)
Right, so acceleration in x = thrust/mass * sin(theta) - g and in y = thrust/mass * cos(theta). derive for velocity(Vx and Vy). The new theta = atan(Vx/Vy). g is gravity acceleration. Repeat. So for a first order, simplified approximation - a 1G rocket doing 20m/s @ 80deg above the horizon will end up going 62m/s @ 62deg above the horizon after about 4 seconds. a 10G rocket starting at 20m/s @ 80deg above the horizon will end up at 421 m/s @ 77deg above the horizon. -- David Masten <[EMAIL PROTECTED]> _______________________________________________ ERPS-list mailing list [EMAIL PROTECTED] http://lists.erps.org/mailman/listinfo/erps-list
