Imagine
class Foo {
function name() {
return "foo"
}
}
class Bar : Foo { // s/:/extends or whatever
function name() {
super.name();
}
}
class Wibble : Bar {
function name() {
super.name();
}
}
the call to super.name() essentially desugars to:
this.__proto__.name.call(this, ...)
But this.__proto__ will be the same everywhere, so someWibble.name() will
infinitely recurse when it reaches Bar::name
Hope this helps.
--Oliver
On Sep 30, 2011, at 7:38 PM, John J Barton wrote:
> On Fri, Sep 30, 2011 at 5:47 PM, Axel Rauschmayer <[email protected]> wrote:
>>
>> Isn't it just a matter of referring to the property with "super"?
>> class Pirate {
>> get name() {
>> return "Captn' " + super.name;
>> }
>> }
>
> just trying to understand: how is super different from __proto__?
> jjb
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