On Sat, Oct 1, 2011 at 2:16 PM, Axel Rauschmayer <[email protected]> wrote:
> Then a super-call is always about letting "this" stay the same, but finding
> a "later" method: If your method lives in O1, you start your search for the
> super-property *after* O1 etc. In code this looks as follows:
> here.__proto__.foo.call(this, …)
> where "here" means "the object that the current method lives in". The
> effect is then:
> - here.__proto__: start your search *after* the method’s object and look
> for "foo".
> - .call(this, …): but keep "this" the same.
Am I right that super-calls only works for class methods, because they know
the, statically determinable, prototype chain of its instances, and
therefore it knows where to start the search.
A normal method, e.g.,
var o = {__proto__: { m: function(x) { alert(x); }};
o.m = function(v) { super(v); }; // doesn't work
o.m("hello");
won't be able to use "super", because it doesn't know where to start the
search - all it knows is the this-argument to the call and the function
itself, which doesn't necessarily mean anything.
/L
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