Here is valid ES6 for-in statement:
for (let p=alert("initializing p"+p) in [0,1]) alert(p);
Each iteration gets a fresh p, but does it produce three alerts saying:
Initializing p
0
1
or four alerts saying
Initializing p
0
Initializing p
1
I would expect the first alternative.
However, taking the first alternative, what happens for
let p="outer";
for (let p=alert("initializing p"+p) in [0,1]) alert(p);
Is the first alert: initializing outer
or does it throw a reference error for a temporal dead zone violation?
I would expect the reference error.
Essentially the for-in is conceptually wrapped with a block that has an
uninitialized binding for p. The initializer of the let declaration is
evaluated once in the scope of that block and then the value is discarded
because it is inaccessible. For each iterations, a fresh block is created
containing a binding for p that is initialized to the current iteration key and
then the statement is evaluated in the scope of that block.
Thoughts?
Allen
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