So why could this not desugar to?:
var myClass = (function(){
var __test;
function myClass() {
__test = 0;
}
myClass.prototype.getTest = function(){ return __test; }
return myClass;
})();
On Mon, Aug 27, 2012 at 11:01 AM, David Bruant <[email protected]> wrote:
> Le 27/08/2012 16:55, Matthew Robb a écrit :
>
> SO it has to be constructed via new Name() or will it automatically
>> create Name objects when it encounters an assignment of that form? If you
>> do have to create it does that mean in order to access it at all you would
>> need to be in scope of myname2?
>>
>> My question I think boils down to whether access is SCOPE gated or OBJECT
>> gated:
>>
>> var myClass = (function(){
>> class myClass {
>> constructor(){
>> this[test] = 0;
>> }
>> }
>>
>> return myClass;
>> })()
>>
>> myClass.prototype.getTest = function() { return this[test] }
>>
>> Is the above perfectly valid?
>>
> This cannot work, because your inherited method needs an access to the
> private name in your variable 'test' (which in your example is neither
> declared nor initialized).
>
> To rewrite your example:
>
> var myClass = (function(){
> var test = new Name();
>
>
> class myClass {
> constructor(){
> this[test] = 0;
> }
>
> getTest: function(){return this[test]};
> }
>
> return myClass;
>
> })();
>
> In this rewritten version, test is being declared in an encapsulating
> function scope, getTest will naturally gets in myClass.prototype (by
> definition of what the class syntax desugars to IIRC) and your inherited
> method will have access to your private name.
>
> David
>
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