I remember that String object iterator produces the sequence of Unicode characters. http://wiki.ecmascript.org/doku.php?id=harmony:iterators#string_iterators
So I think we can get code points by using array comprehension, var points = [ch for ch of string]; Is it right? > all On Sat, Dec 1, 2012 at 5:33 AM, Mathias Bynens <[email protected]> wrote: > ECMAScript 6 introduces some useful new features that make working with > astral Unicode symbols easier. > > One thing that is still missing though (AFAIK) is an easy way to count the > number of symbols / code points in a given string. As you know, we can’t > rely on `String.prototype.length` here, as a string containing nothing but > an astral symbol has a length of `2` instead of `1`: > > > var poo = '\u{1F4A9}'; // U+1F4A9 PILE OF POO > > poo.length > 2 > > Of course it’s possible to write some code yourself to loop over all the > code units in the string, handle surrogate pairs, and increment a counter > manually for each full code point, but that’s a pain. > > It would be useful to have a new property on `String.prototype` that would > return the number of Unicode symbols in the string. Something like > `realLength` (of course, it needs a better name, but you get the idea): > > > poo.realLength > 1 > > Another possible solution is to add something like > `String.prototype.codePoints` which would be an array of the numerical code > point values in the string. That way, getting the length is only a matter > of accessing the `length` property of the array: > > > poo.codePoints > [ 0x1F4A9 ] > > poo.codePoints.length > 1 > > Or perhaps this would be better suited as a method? > > > poo.getCodePoints() > [ 0x1F4A9 ] > > poo.getCodePoints().length > 1 > > Has anything like this been considered/discussed here yet? > _______________________________________________ > es-discuss mailing list > [email protected] > https://mail.mozilla.org/listinfo/es-discuss > -- Regards, Yusuke Suzuki
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