Brendan Eich wrote:
Herby Vojčík wrote:
That is, these are identical, except the syntax:
r = o.p.q {p: {q: r}} = o
r = o.?p.q {?p: {q: r}} = o
P=o.p; Q=o.?q {p: P, ?q: Q} = o
Here I part company only on syntax:
r = o?.p.q {p?: {q: r}} = o
P=o.p; Q=o?.q {p: P, q?: Q} = o
And of course, the short-hand works:
p=o.p; q=o?.q {p, q?} = o
Oh, now that I see details, I do not like the syntax, because the
symmetry of use of ? vanished.
Compare:
r = o.?p.q {?p: {q: r}} = o // in both forms, "?p"
vs,
r = o?.p.q {p?: {q: r}} = o // 1st: "o?"; 2nd: "p?"
And:
p=o.p; q=o.?q {p, ?q} = o // I can say informally
// o.{p, ?q} meaning
// {o.p, o.?q}
vs.
p=o.p; q=o?.q {p, q?} = o // 1st: "o?(.q)", 2nd: "(o.)q?"
But of coures, if it has some serious problems / is unacceptable from
other reasons, then different syntax must be used.
/be
Herby
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