does that work runtime with more than one super ?
On Fri, Mar 8, 2013 at 7:13 PM, Axel Rauschmayer <[email protected]> wrote: > Now, how transpilers are going to solve Object.mixin super call? 'cause > once again, that should be solved runtime and I am curious, without caller, > how transpilers are thinking to solve that. > > > You can do the following: > > SubClass.prototype.foo = function me(x) { > var ssuper = me.homeObject.__proto__; > return 1 + ssuper.foo.call(this, x); > }; > > Additionally, one would have to make the following assignment for each > method m of SubClass.prototype: > > SubClass.prototype.m.homeObject = SubClass.prototype; > > Rationale: a method needs to be aware of its (static) position in the > prototype chain if it wants to make a proper super-reference. > > More information: http://www.2ality.com/2011/11/super-references.html > > -- > Dr. Axel Rauschmayer > [email protected] > > home: rauschma.de > twitter: twitter.com/rauschma > blog: 2ality.com > >
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