On Tue, Dec 3, 2013 at 9:13 PM, Waldemar Horwat <[email protected]> wrote:
> On 12/03/2013 05:30 PM, Mark S. Miller wrote:
>
>> What's ^^ ?
>>
>
> a^^b would essentially be the same as !a!=!b except that it would return
> the actual truthy value if it returns true.
Those semantics are extremely error-prone. `(("foo" ^^ "bar") ^^ "baz") !==
("foo" ^^ ("bar" ^^ "baz"))`, and I doubt anyone will remember which
corresponds to `"foo" ^^ "bar" ^^ "baz"`?
Also, the syntax gives the impression that this is a short-circuiting
operator since it is a "doubled bitwise operator" like || and &&, but it
can't be short-circuiting.
-- Sean Silva
>
>
> Waldemar
>
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