There are times where I would like to check whether a string has every
occurrence of certain strings/numbers:
```
var str = "John, Mary, Bob, Steve";
str.includes(["Mary", "Bob"]); // true
var str2 = "John, Mary, Steve";
str2.includes(["Mary", "Bob"]); // false
```
So the way the above would work would be as an AND operation. Meaning
having all of the instances of the array past in.
To use `String.prototype.includes` as an OR operation with the first
parameter being an array, wouldn't be necessary because you can use a
regular expression for that:
```
var str = "John, Mary, Bob, Steve";
(/Mary|Bob/g).test(str); // true
var str2 = "John, Mary, Steve";
(/Mary|Bob/g).test(str2); // true
```
As of right now `String.prototype.includes` called with an array as the
first parameter will call `.toString()` on the array resulting in the
following:
```
var str = "Hello World";
str.includes(["Hello", "World"]); //false because it calls ["Hello",
"World"].toString() == "Hello,World";
```
Pretty useless!!!
Now to achieve what I would like `String.prototype.includes` to accomplish
with an array as the first parameter, I currently take the following
approach:
```
var str = "John,Mary,Bob,Steve";
var names = ["Mary", "Bob"];
names.every(name => str.includes(name)); // true;
//Or perhaps make it a function:
function stringIncludes(str, names) {
if(names) {
return names.every(name => str.includes(name));
}
return false;
}
Thanks.
_______________________________________________
es-discuss mailing list
[email protected]
https://mail.mozilla.org/listinfo/es-discuss
