They diverge if a constructor makes a super-constructor call: The last constructor in a chain of super-constructor calls allocates the instance and it has to use `newTarget.prototype` as the prototype. `newTarget` is first filled in by the `new` operator and later passed on by `super`.
This is roughly similar to making super-method calls where `this` has to remain the same, because the super-method has to access the same instance properties. > On 16 Mar 2015, at 18:32, Coolwust <[email protected]> wrote: > > From ES 6, section 7.3.14, there is an abstract operation `Construct (F, > [argumentsList], [newTarget])`, so if I have the following code `var foo = > new bar()`, then `newTarget` is the same as `F`, which is `bar`. > > My question is, in what situation, `F` is **NOT** the same as `newTarget`? > And what is `newTarget` really? -- Dr. Axel Rauschmayer [email protected] rauschma.de
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