Thanks very much for the explanation! it's clear now. On Mon, Mar 16, 2015 at 1:58 PM, Allen Wirfs-Brock <[email protected]> wrote:
> > On Mar 16, 2015, at 10:32 AM, Coolwust wrote: > > From ES 6, section 7.3.14, there is an abstract operation `Construct (F, > [argumentsList], [newTarget])`, so if I have the following code `var foo = > new bar()`, then `newTarget` is the same as `F`, which is `bar`. > > My question is, in what situation, `F` is **NOT** the same as `newTarget`? > And what is `newTarget` really? > > > super() calls within constructors > > see > http://people.mozilla.org/~jorendorff/es6-draft.html#sec-super-keyword-runtime-semantics-evaluation > > 3rd algorithm > > allen > > >
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