How about something like...
Array.prototype.fill = function(filler, times, flatten) {
var ret = [].concat(this);
var len = Number(times) || 0;
var (var i=0; i<len; i++) {
if (flatten && Array.isArray(filler)) {
ret.push.apply(ret, filler);
} else {
ret.push(filler);
}
}
return ret;
}
[].fill(0, 3) // [0, 0, 0]
[].fill(['a', 'b'], 2) // [['a', 'b'], ['a', 'b']]
[].fill(['a', 'b'], 2, true) // ['a', 'b', 'a', 'b']
--
Michael J. Ryan - http://tracker1.info
On Mon, Mar 26, 2018 at 12:02 PM Cyril Auburtin <[email protected]>
wrote:
> > maybe fill with incrementing number?
>
> ```js
> Array.from({length: 6}, (_, i) => i)
> ```
>
> > Are there use cases for filling with alternating values, as in `['x',
> 'y'].repeat(3)`?
>
> Not so many, but for example when working with flat matrices,
> `[0,0,255,1].repeat(len)` for generating quickly a uniform imageData
>
> But even with one item, I find `[x].repeat(n)` more explicit than the 2
> other alternatiives
>
> It's somewhat close to array comprehensions (that I don't really miss
> though)
>
>
> 2018-03-26 15:27 GMT+02:00 Jerry Schulteis <[email protected]>:
>
>> Whatever the use cases might be, I like generators and spread for filling
>> an array with values, e.g.:
>>
>> ```js
>> function* repeat(n, ...values) {
>> for (let i = 0; i < n; ++i) {
>> yield* values;
>> }
>> }
>>
>> [...repeat(3, 'x', 'y')]
>> ```
>>
>>
>> On Sunday, March 25, 2018, 3:41:10 PM CDT, Claude Pache <
>> [email protected]> wrote:
>>
>>
>> [...]
>>
>> For filling a new array with one value, `Array(n).fill('foo')` seems
>> reasonable to me.
>>
>> Are there use cases for filling with alternating values, as in `['x',
>> 'y'].repeat(3)`?
>>
>>
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