First, Array.prototype.fill(value[, start[, end]]) already exists, so you need
a new name (I'll provisionally use mjrFill).
Second, Boolean arguments in an API are a pet peeve of mine, in
```js[].mjrFill(['a', 'b'], 2, true)```it is not obvious what the third
argument means.
Third, what was originally asked for was Array.prototype.repeat, analogous to
String.prototype.repeat(count), which returns a new string consisting of the
specified number of copies of the original, so:
```js[0].repeat(3) // [0, 0, 0][['a', 'b']].repeat(2) // [['a', 'b'], ['a',
'b']]
['a', 'b'].repeat(2) // ['a', 'b', 'a', 'b']
[].mjrFill(arrayThatNeedsFlattening, n, true) // What does this do?
arrayThatNeedsFlattening.flatten().repeat(n); // Hard to misunderstand.
```
On Tuesday, March 27, 2018, 7:25:07 PM CDT, Michael J. Ryan
<[email protected]> wrote:
How about something like...
Array.prototype.fill = function(filler, times, flatten) { var ret =
[].concat(this); var len = Number(times) || 0; var (var i=0; i<len; i++) {
if (flatten && Array.isArray(filler)) { ret.push.apply(ret, filler); }
else { ret.push(filler); } } return ret;}
[].fill(0, 3) // [0, 0, 0][].fill(['a', 'b'], 2) // [['a', 'b'], ['a',
'b']][].fill(['a', 'b'], 2, true) // ['a', 'b', 'a', 'b']
--
Michael J. Ryan - http://tracker1.info
On Mon, Mar 26, 2018 at 12:02 PM Cyril Auburtin <[email protected]>
wrote:
> maybe fill with incrementing number?
```jsArray.from({length: 6}, (_, i) => i)```
> Are there use cases for filling with alternating values, as in `['x',
>'y'].repeat(3)`?
Not so many, but for example when working with flat matrices,
`[0,0,255,1].repeat(len)` for generating quickly a uniform imageData
But even with one item, I find `[x].repeat(n)` more explicit than the 2 other
alternatiives
It's somewhat close to array comprehensions (that I don't really miss though)
2018-03-26 15:27 GMT+02:00 Jerry Schulteis <[email protected]>:
Whatever the use cases might be, I like generators and spread for filling an
array with values, e.g.:
```jsfunction* repeat(n, ...values) { for (let i = 0; i < n; ++i) { yield*
values; }}
[...repeat(3, 'x', 'y')]
```
On Sunday, March 25, 2018, 3:41:10 PM CDT, Claude Pache
<[email protected]> wrote:
[...]
For filling a new array with one value, `Array(n).fill('foo')` seems reasonable
to me.
Are there use cases for filling with alternating values, as in `['x',
'y'].repeat(3)`?
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