I think the problem happens when the constant current charger doesn't stop when 
the cells are full.  The cell can't store the energy, but it has to go 
somewhere.  They are sealed, so it can't just bubble off water like lead-acid 
cells do.  The energy breaks down the electrolyte and builds pressure until the 
cell finally blows.

Once full, I don't think it matters how large or small the current is.  It will 
cause damage and it is additive.

Mike

On April 1, 2015 10:33:42 PM MDT, Jan Steinman via EV <[email protected]> wrote:
>> From: Robert Bruninga via EV <[email protected]>
>> 
>> That's 300 mA at 250 VDC.
>
>The voltage doesn't really matter, does it?
>
>If you're charging with a constant-current source, all but one of the
>cells could short, and the last cell would still see no more than 360
>mW.
>
>If you were charging constant-voltage, and you had a cell short, then
>that would cause the other cells to receive more current, which could
>cause them to short, etc. until you burn up the string. But it
>shouldn't happen on a correctly-operating constant-current charger, no?
>
>:::: Jan Steinman, EcoReality Co-op ::::
>
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