Le 13-juil.-05, à 06:02, Russell Standish a écrit :
Complex numbers indeed do not have an ordering (being basically points on a plane)
So you pretend the axiom of choice is false. It is easy to build an ordering of the complex numbers through it.
There is no ordering *which satisfies some algebraic desiderata*. But as a set, you can always ordered it (given that the axiom of choice is consistent with ZF).
Bruno http://iridia.ulb.ac.be/~marchal/