On 10/20/2025 10:52 PM, Alan Grayson wrote:

            Sure.  Consider a sequence of n=4 Bernoulli trials.  Let
            h be the number of heads.  Then we can make a table of
            the number of all possible sequences bc with exactly h
            heads and with the corresponding observed proportion h/n

                 h       bc       h/n
                0         1        0.0
                1         4        0.25
                2         6        0.5
                3         4        0.75
                4         1        1.0

            So each possible sequence will correspond to one of
            Everett's worlds.  For example hhht and hthh belong to
            the fourth line h=3. There are sixteen possible
            sequences, so there will be sixteen worlds and a
            fraction 6/16=0.3125 will exhibit a prob(h)~0.5.

            But suppose it was an unfair coin, loaded so that the
            probability of tails was 0.9.  The possible sequences
            are the same, but now we can apply the Born rule and
            calculate probabilities for the various sequences, as
            follows:

                 h       bc       h/n     prob
                0         1        0.0      0.656
                1         4        0.25    0.292
                2         6        0.5      0.049
                3         4        0.75    0.003
                4         1        1.0      0.000

            So  most of the observers will get empirical answers
            that differ drastically from the Born rule values.  The
            six worlds that observe 0.5 will be off by a factor of
            1.8. And notice the error only becomes greater as longer
            test sequences are used.  The number of sequences peak
            more sharply around 0.5 while the the Born values peak
            more sharply around 0.9.

            Brent

            *By the above paragraph, it seems you've already
            falsified the MWI, except that you could claim that's
            what no-collapse yields in this-world. I don't see any
            reason for claiming each sequence is observed in
            different worlds. AG*

    There's no unique sequence "in this world" because there's no
    unique "this world" in MWI.

    Brent

*
*
*IMO this is ridiculous. How can you disprove the MWI when you accept its foolish claim of many worlds? All that's required is to show that the no-collapse hypothesis gives wrong results compared to Born's rule in the only world you know for sure, THIS-WORLD. AG*
The no collapse hypothesis gives wrong results in some worlds and not in others.  The problem is how you assign probabilities to these worlds.  MWI advocates use the Born rule to assign probabilities to the different branches and so produce /an interpretation empirically identical/ to the neo-Copenhagen interpretation.  I think it fails in the sense that it can produce many observers, even a majority, existing in low probability branches who cannot know they are in low probability branches and so are deceived by their observations into falsifying QM.  MWI dismisses them as low probability even though they are numerous.  Copenhagen says "low probability" means they likely don't exist.  So it is a philosophical disagreement about the meaning of applied probability.

Brent
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