OK, I see my mistake. I was looking at whether the swapping was order
independent.
But your post, /"and because they are Non-Abelian, swapping M1 and M2
and then M2 and M3, gives a different result than swapping M2 and M3,
and then M1 and M2."/ is unnecessarily complicated. Swapping M1 and M2
gives a different results if they are non-Abelian.
Brent
On 1/21/2026 5:16 AM, John Clark wrote:
On Tue, Jan 20, 2026 at 4:02 PM Brent Meeker <[email protected]>
wrote:
//
/> Doesn't that give different results whether they are Abelian or
not.
m1, m2, m3 -> m2,m1,m3 -> m3,m1,m2
m1, m2, m3 -> m1,m3,m2 -> m2,m3,m1/
*If the interactions with the following particles _are __Abelian_then
the final result of*
*
*
*{ [(M1*M2)*M3]*(M2*M1)*M3*] }*(M3*M1)*M2*
*
*
*would be _identical_ to the final result ofthe following reactions
*
*
*
*{ [(M1*M2)*M3]*(M1*M3)*M2*] }*(M2*M3)*M1 *
*
*
*But if you do the same thing with particles that _areNOT Abelian_then
those two results would NOT be the same. *
*
*
*John K Clark See what's on my new list at Extropolis
<https://groups.google.com/g/extropolis>*
eh7
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