On Wed, Jan 21, 2026 at 9:35 PM Brent Meeker <[email protected]> wrote:
> > * > OK, I see my mistake. I was looking at whether the swapping was order > independent. But your post, "and because they are Non-Abelian, swapping M1 > and M2 and then M2 and M3, gives a different result than swapping M2 and > M3, and then M1 and M2." is unnecessarily complicated. Swapping M1 and M2 > gives a different results if they are non-Abelian.* > *I used that as an example because not only does it demonstrate how exotic non-Abelian particles can encode information in ways that regular everyday Abelian particles cannot, it also shows how that information can be used to perform calculations that Abelian particles cannot. * * John K Clark See what's on my new list at Extropolis <https://groups.google.com/g/extropolis>* 6hu eh7 Brent > > On 1/21/2026 5:16 AM, John Clark wrote: > > On Tue, Jan 20, 2026 at 4:02 PM Brent Meeker <[email protected]> > wrote: > > >> >> * > Doesn't that give different results whether they are Abelian or not. >> m1, m2, m3 -> m2,m1,m3 -> m3,m1,m2 m1, m2, m3 -> m1,m3,m2 -> m2,m3,m1* >> > > *If the interactions with the following particles are Abelian then the > final result of* > > *{ [(M1*M2)*M3]*(M2*M1)*M3*] }*(M3*M1)*M2* > > > *would be identical to the final result of the following reactions * > > *{ [(M1*M2)*M3]*(M1*M3)*M2*] }*(M2*M3)*M1 * > > *But if you do the same thing with particles that are NOT Abelian then > those two results would NOT be the same. * > > > >> -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion visit https://groups.google.com/d/msgid/everything-list/CAJPayv0LNszvvTfSCxP7h8-C9sn4CD9f4xC4RUKctqUbNWe3rQ%40mail.gmail.com.
