On Sat, Feb 1, 2014 at 7:57 AM, Edgar L. Owen <edgaro...@att.net> wrote:

> One might think it was the acceleration that slowed time on A's clock,
> BUT the point is that A's acceleration was only 1g throughout the entire
> trip which was exactly EQUAL to B's gravitational acceleration back on
> earth. So if the accelerations were exactly equal during the entire trip
> how could A's acceleration slow time but B's not slow time by the same
> amount?
>

If A were going into space and accelerating upward off the surface of the
Earth at one g (32 feet per second per second), then he would be
experiencing 2g, one g from the Earth and one g from his continuing change
in upward velocity.

> both = 1g throughout the entire trip
>

No, not during the entire trip. And if the space traveler ever wants to
return to Earth to rejoin his friend so they can directly compare their
clocks then he's going to have to change the direction of his acceleration
by 180 degrees. So their clocks will not match because their travel
experiences were not symmetrical.

  John K Clark

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