John, 1. No. because both A and B experience the exact same 1g acceleration for the entire trip. A's watch doesn't suddenly spring back thousands of year in the second he finally cuts off his acceleration.
2. This example comes from Kip Thorne who provides the calculations. If the results of your calculations differ from Thorne's you might want to double check them... 3. OK. Pick the point of origin as moving with A instead of remaining with B back on earth. Yes, you WILL get the same answer. That is exactly my point. Both A and B will each see each other's clock slowing but when A reaches his destination only his clock will ACTUALLY be slowed, and both A and B will agree on that. AND the accelerations of both A and B are both exactly equal 1g during the entire trip. So why is that? Edgar On Tuesday, February 4, 2014 1:02:52 PM UTC-5, John Clark wrote: > > On Mon, Feb 3, 2014 at 3:29 PM, Edgar L. Owen <[email protected]<javascript:> > > wrote > > > The question is why when A gets to the center of the galaxy and stops >> > > That's the key point to remember, A comes to a stop. And during the > deceleration process things would no longer be symmetrical, A would see B's > clock running Fast but B would see A's clock running slow. So A would have > aged less than B. > > > relative to B that then his clock shows only 20 years passage, but B's >> clock shows 30,000+? >> > > Actually if you work out the numbers you find that if A accelerated at one > g for 20 years ship time he'd only be 137 light years from Earth. After 40 > years ship time A would be 17,600 light years from Earth, and after 60 > years ship time A would be 2,480,000 light years from Earth and be at the > Andromeda Galaxy, although we on the Earth would have to wait 5 million > years to see A's ship get to Andromeda, and unfortunately he'd be going > much too fast to stop and sightsee. > > >> > Perhaps you didn't see my similar questions to Brent, to which he has >> either been unwilling or unable to reply, about this case. He says it's a >> matter of geometry, but neglects to point out that geometry must have its >> origin at B's earth bound frame. >> > > You can pick any point of origin and you will get the same answer, but > it's wise to pick an origin that makes the mathematics the easiest. > > John K Clark > > > > > > -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/groups/opt_out.
