On 6 March 2014 22:06, Bruno Marchal <[email protected]> wrote:

>
> Liz, meanwhile you might try this one, which is a bit more easy than the
> transitivity case:
>
> Show that (W,R) respects []A -> <>A if and only if R is ideal.
>
> (I remind you that R is ideal means that there is no cul-de-sac world at
> all in (W,R)).
>

OK, I consult my diary and...

Ideal is as you say, yes! :-)

So []A -> <>A means that A is some proposition universally true in an
illuminated, accessible multiverse, and this implies that A is possible in
that multiverse.

Hang on I must be missing something. That seems trivially obvious! Maybe
you could point out what I've misunderstood here...

Let me try again.

[]p means that for any world alpha, p is true in all worlds accessible from
alpha. (Doesn't it? Well if p is a proposition, which might be 'x is false'
then that seems reasonable).

And <>p means that, ah, ~[]~p iirc. Which is to say it isn't true that
there is a world accessible from alpha in which ~p.

But isn't that implied by []p? I must have a definition wrong somewhere.


>
> Do you see that (W, R) is reflexive entails that (W,R) is ideal?   If all
> worlds access to themselves,  no world can be a cul-de-sac world, as a
> cul-de-sac world don't access to any world, including themselves.
>

Reflexive is alpha R alpha for all alpha, so no cul de sac is possible.

>
> Bruno
>
>
>
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