On 7 May 2014 07:53, John Ross <[email protected]> wrote: > According to my theory: > > > > Pair production is the combination of the three entrons of three photons: > > 1) A 1.02 MeV gamma ray photon > > 2) A 928 MeV neutrino photon > > 3) A 1.12 KeV photon > > These photons are resonant with each other. In thepair production process > the all of the entrons/photons disappear. > > > > When the positron combines with the electron in the annihilation event you > get two 0.51 MeV entron/photons and a 928 MeV neutrino entron/photon which > is not detected because it normally passes through planets without > interacting with anything. > > > A 928 MeV photon is about 900 x as energetic as a gamma ray photon. I imagine that would be fairly detectable, as would the equivalent mass before annihilation. The mass of an electron is about 0.5 MeV, so that leaves some 927 MeV unaccounted for.
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