On Tue, May 6, 2014 at 3:53 PM, John Ross <[email protected]> wrote:
> According to my theory: Pair production is the combination of the three > entrons of three photons: > > 1) A 1.02 MeV gamma ray photon > 2) A 928 MeV neutrino photon > > 3) A 1.12 KeV photon > Huh? I know what a electron neutrino is and I known what muon neutrinos and a tau neutrinos are; and I know what a photon is too, but I have no idea what a "neutrino photon" is. Photons involve electromagnetism but neutrinos don't feel that force, they only feel the Weak Nuclear Force and Gravity, and that's why they're so hard (but not impossible) to detect. If neutrino's felt electromagnetism they'd be easy to detect. > > When the positron combines with the electron in the annihilation event > you get two 0.51 MeV entron/photons and a 928 MeV neutrino entron/photon > I don't know what a "entron" is either but I don't need to to know that your theory must be wrong. Both electrons and positrons have .51 MeV of energy, so before they interact there was .51 +.51 = 1.02 Mev, but after they interact there was .51 + .51 + .928 = 1.948 MeV of energy. So regardless of what "entron" means unless you can prove that 1.02 = 1.948 your theory violates the law of conservation of energy. John K Clark -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/d/optout.
