On Wed, May 07, 2014 at 09:51:31AM +1200, LizR wrote:
> On 7 May 2014 04:58, John Clark <[email protected]> wrote:
> 
> > On Mon, May 5, 2014 at 2:56 PM, John Ross <[email protected]>wrote:
> >   > When electrons and positrons are destroyed at least two photons are
> > produced (my model says there are three photons produced).
> >
> >>
> > Then there is solid evidence your theory is wrong. The mass of the
> > electron (and the positron) is 9.1 *10^-31  kilograms, and  from E=MC^2 we
> > can figure out that's equivalent to 511kev of energy. Gama ray photons of
> > exactly 511kev have been detected in electron positron experiments
> > performed in particle accelerators and they have also been found radiating
> > from the center of our galaxy. This indicates that  2 photons were produced
> > when electrons and positrons annihilate each other;  if it were three we
> > wouldn't see that, we'd see Gamma rays of 341kev because (511+511)/3 = 341.
> >
> 
> True, although one could postulate a very very very low energy third photon
> on just that basis, currently undetectable. Are any other quantum numbers
> involved that might firm up this argument? (What happens to the
> electron/positrons' spin? Does it go into the photons' polarisation? (wild
> guess!))
> 

Conservation of momentum is perhaps a more stringent test here. A third
undetectable photon would show up as a momentum deficit in the pair of
photons that are observed.

Exactly that effect lead to the experimental discovery of the neutrino
in the first place.

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