On 6/6/2014 7:54 PM, LizR wrote:
On 7 June 2014 14:00, John Ross <[email protected]
<mailto:[email protected]>> wrote:
If you had a copy of my book you would see that the center portion of the
alpha is comprised of four circling protons and two electrons are circling
the path of the four protons, so the alpha particle is positive on the
inside and negative on the outside. (FIG 11 ON PAGE 97 is a drawing of an
alpha particle.) The result is that the combination of two alpha particles
is extremely unstable, but the combinations of 3 through 10 alpha particles
are all totally stable. In these nuclei the four positive protons in the
center of the alpha is attracted to the two electrons in outside portion of
its neighbor alpha particle. So, for example in the carbon-12 nucleus, at
the right distances the attractive Coulomb forces in the three alpha
particles exactly balance the repulsive coulomb forces, so carbon-12 is
stable. NO STRONG FORCE NEEDED!
So doesn't the strong force account for anything else? (Honest question, I don't know if
there is any other need for it apart from holding nuclei together).
But the strong force needs to be short range while the EM force is long range. Otherwise,
even if there were and equilibrium point, a nucleus wouldn't be stable.
Brent
Does your model account for what happens in high energy collisions between nuclei, as
for example in a collider or when a cosmic ray enters the atmosphere? I believe that
stuff involves quark jets and production of various short lived particles (e.g. the
Higgs boson) and all sorts of other stuff that is explained quite well by the existing
model. Have you examined any of this any can you similarly account for it?
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