Quantum measure is the result of solving Schrodinger's Eq.
yielding a different probability for each quantum state
 and a different measure for each different scenario
unlike the invariant measure of the reals.
Do you disagree?
Richard


On Thu, Jul 3, 2014 at 12:44 AM, Russell Standish <li...@hpcoders.com.au>
wrote:

> On Thu, Jul 03, 2014 at 12:23:35AM -0400, Richard Ruquist wrote:
> > On Wed, Jul 2, 2014 at 10:34 PM, Russell Standish <li...@hpcoders.com.au
> >
> > wrote:
> >
> > > On Tue, Jul 01, 2014 at 04:30:52PM -0400, Stephen Paul King wrote:
> > > > Hi Russell,
> > > >
> > > > Ah! I don't quite grok it completely, but thank you for this
> example. We
> > > > had to assume an already existing measure on the Reals. Where does
> that
> > > > come from?
> > > >
> > >
> > > The standard measure on the reals is based on the observation that we
> > > expect the set of real numbers starting with 0.110... to have the same
> > > measure as those starting with 0.111... That would be a reasonable
> > > default assumption for most purposes.
> >
> >
> > The measure obtained by compression of the reals in binary form is close
> to
> > the quantum mechanic measure, but not exact.
> > In fact, the quantum measure varies with the scenario, whereas the
> measure
> > of the reals is invariant.
> > Richard
> >
>
> What do you mean? What is this "quantum measure"?
>
> --
>
>
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