To a second approximation, the afore-mentioned cancellation can be made very exact by giving each particle a partner which exactly balances its contribution (or words to that effect). These are the "superpartners", and give a fermion for each known boson and vice versa. Since fermions and bosons have opposite effects in renormalisation, these could be made to cancel out exactly if these were identical apart from their spins. But since these superpartners haven't been observed they must have a greater mass than their mundane partners, this being a broke symmetry. However they can still cancel to high precision...
...unless I am still barking up the wrong branch of the Feynman diagram, of course. -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to everything-list+unsubscr...@googlegroups.com. To post to this group, send email to everything-list@googlegroups.com. Visit this group at http://groups.google.com/group/everything-list. For more options, visit https://groups.google.com/d/optout.
