On Sunday, March 11, 2018 at 10:30:46 AM UTC-4, agrays...@gmail.com wrote:
>
>
>
> On Saturday, March 10, 2018 at 10:54:50 PM UTC-5, Brent wrote:
>>
>>
>>
>> On 3/10/2018 7:32 PM, agrays...@gmail.com wrote:
>>
>>
>>
>> On Saturday, March 10, 2018 at 10:09:45 PM UTC-5, Brent wrote: 
>>>
>>>
>>>
>>> On 3/10/2018 5:04 PM, agrays...@gmail.com wrote:
>>>
>>>
>>>
>>> On Sunday, March 4, 2018 at 11:35:24 PM UTC-5, agrays...@gmail.com 
>>> wrote: 
>>>>
>>>> I don't think so. I think its equations of motion mix time and space, 
>>>> so if time increases, spatial position must change. That is, the 
>>>> assumption 
>>>> that time increases, produces changes in spatial position. CMIIAW. AG
>>>>
>>>
>>> Here's a related question; if you assume a 4d spacetime manifold, how 
>>> does one imagine the shortest path between two points, aka a geodesic path, 
>>> using the Lorentzian metric? AG 
>>>
>>>
>>> In the Lorentz metric a geodesic is the longest path between two 
>>> time-like events.
>>>
>>> Brent
>>>
>>
>> Right; we've discussed this in the past. But if that's true, why choose 
>> motion along a geodesic in spacetime for a model of gravity 
>>
>>
>> He didn't "choose" it, it's implicit in the motion being force-free.  As 
>> Russell pointed out it's implied by conservation of energy-momentum.
>>
>> Brent
>>
>
> Where exactly is it argued that conservation of energy-momentum implies 
> motion along a geodesic in the absence of external forces? TIA, AG 
>

I suppose, for say a Lorentzian metric, one could define a geodesic as the 
path where the length between two points is maximal, that it's unique, and 
all other paths do not conserve energy-momentum.  Offhand, the proof 
doesn't seem obvious. Does Epstein do it? AG

> if it's the LONGEST path between two time-like events. Wasn't Einstein 
>> motivated by the fact that a geodesic along a sphere using the Euclidean 
>> metric for path length, is the SHORTEST distance between two points on a 
>> sphere? AG
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