On Thu, Mar 14, 2019 at 10:50 AM Lawrence Crowell <
goldenfieldquaterni...@gmail.com> wrote:

> An entanglement can swap or a bipartite entanglement can enter into an
> entanglement with another state. So the entangled state c(|+>_1|->_2 +
> |->_1|+>_2) can couple with the system in a superposition c(|←> + |→>) to
> become, depending upon the interaction and conservation principles etc to
> be
>
> c(|+>_1|->_2 + |->_1|+>_2) + c(|←> + |→>) → b(|+>_1|←> + |->_1|→>) + d(|->_2
> + |+>_2)
>
> which would be an entanglement swap. It might however form a tripartite
> entanglement
>
> c(|+>_1|->_2 + |->_1|+>_2) + c(|←> + |→>) →
>
> b(|+>_1|->_2|←> + |->_1|+>_2|→>) + c(|->_1|+>_2|←> + |+>_1|->_2|→>).
>
> Here normalization factors can be easily calculated. For the first to
> happen there is a Hadamard gate on the two initial states. For the second
> there are CNOT type operations that creates an entanglement. CNOT gates
> demolish or generate entanglements.
>

I do not really understand this. Particles 1 and 2 are entangled, say in
the singlet state as above. But the particles are well separated, so any
interaction with a third particle can affect only one of the two originals.
This seems to be what your first possibility shows -- the interaction of
one of the entangled pair with a third particle destroys the original
entanglement, but might result in the interacting particle becoming
entangled with the third particle. Except that your expansion seems to deny
the non-separability of the initial entangled state.

The second possibility you list seems to deny the non-separability of the
initial state right from the start -- only one of the initial particles can
interact with the third particle, and that does not entangle the
non-interacting partner.

Bruce

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