> On 12 Aug 2019, at 04:06, Bruce Kellett <[email protected]> wrote:
> 
> On Mon, Aug 12, 2019 at 3:48 AM Bruno Marchal <[email protected] 
> <mailto:[email protected]>> wrote:
> On 9 Aug 2019, at 13:15, Bruce Kellett <[email protected] 
> <mailto:[email protected]>> wrote:
>> On Fri, Aug 9, 2019 at 7:49 PM Bruno Marchal <[email protected] 
>> <mailto:[email protected]>> wrote:
>> On 9 Aug 2019, at 04:07, Bruce Kellett <[email protected] 
>> <mailto:[email protected]>> wrote:
>>> From: Bruno Marchal <[email protected] <mailto:[email protected]>>
>>>>> On 8 Aug 2019, at 13:59, Bruce Kellett <[email protected] 
>>>>> <mailto:[email protected]>> wrote:
>>>>> 
>>>>> On Thu, Aug 8, 2019 at 8:51 PM Bruno Marchal <[email protected] 
>>>>> <mailto:[email protected]>> wrote:
>>>>> If the superposition are not relevant, then I don’t have any minimal 
>>>>> physical realist account of the two slit experience, or even the 
>>>>> stability of the atoms.
>>>>> Don't be obtuse, Bruno. Of course there is a superposition of the paths 
>>>>> in the two slit experiment. But these are not orthogonal basis vectors. 
>>>>> That is why there is interference.
>>>> 
>>>> But each path are orthogonal. See the video of Susskind, where he use 1 
>>>> and 0 to describe the boxes where we can find by which hole the particles 
>>>> has gone through. Then, without looking at which hole the particle has 
>>>> gone through, we can get the interference of the wave which is obliged to 
>>>> be taken as spread on both holes, and that represent the superposition of 
>>>> the two orthogonal state described here as 0 and 1.
>>> I seldom watch long videos of lectures. But if Susskind is saying that the 
>>> paths taken by the particle through the two slits are orthogonal then he is 
>>> flatly wrong. Writing the paths as 1 and 0 does not make them orthogonal. 
>>> And if they were orthogonal they could not interact, and you would not get 
>>> interference. Two states |0> and |1> are orthogonal if their overlap 
>>> vanishes: <0|1> = 0. Interference comes from the overlap, so if this 
>>> vanishes, there is no interference.
>>> Either Susskind is terminally confused, or you have misrepresented him.
>>> 
>>> 
>> Or maybe you are wrong. Slit one is orthogonal to slit two, as much as spin 
>> in different direction.
>> 
>> When you observe which slit the particle went through, then yes -- the slits 
>> are then orthogonal eigenstates of the position operator.
> 
> OK. But without collapse, the observation of which slit the particle was 
> taking is only self-entanglement, and it makes the whole history “the 
> particle went through slit A + me seeing the particles going through slit A” 
> orthogonal to the whole history “the particle went through slit B + me seeing 
> the particles going through slit B”.
> 
> So, like I said, the slits are orthogonal if measured.  This is irrelevant to 
> the interference at the screen, because it is the photon waves at the screen 
> that interfere, not the slits. Orthogonal states do not interfere.
> 
> Decoherence is only self-entanglement. It spread at the speed of light, or a 
> bit below, in the environment, making hard to fuse the histories again, 
> through “amnesia”, but that explains why the superposition states are are 
> hard to maintain accessible. FAPP, we can forget the parallel histories, but, 
> only FAPP!
> 
> FAPP is the way we do physics. Metaphysics is for the birds that can't fly!
>  
>> The interference comes from the fact that we get a superposition of going 
>> through slit one + going through slit two when we send a planar 
>> monochromatic wave on the wall with the two slits, and don’t measure which 
>> slit the particle go through.
>> 
>> Yes, then the states that we are measuring are not orthogonal. You do not 
>> get interference between orthogonal states.
>>  
>> That is how Susskind explains the two slit experiment in term of 
>> entanglement. You don’t need to look at the whole video, I gave the position 
>> of this sub-talk in the video.
>> 
>> Any crisp measurement, like “which slit” gives rise to orthogonal state, 
>> which can interfere when superposed.
>> 
>> Which is essentially what I said -- orthogonal states do not interfere.
> 
> In the sense you mention I am OK, but we have a slight vocabulary problem. 
> Not important, if you agree that measurement are self-entanglement, so that 
> the superposition of the orthogonal state SlitA and SlitB, say some oblique 
> (with sqrt(2) = 1) SlitA + SlitB is inherited by the observer “looking” which 
> is which.
> 
> If you do not measure which slit the photon went through, then the 
> superposition of slits is not broken by decoherence.

Decoherence break things only if there is a collapse. Without collapse, even if 
I measure which slit the photon went through, the two terms of the 
superposition continue to exist, describing me seeing both outcomes, and both 
me feel like if there has been a collapse, and that decoherence is physical 
real, but that illusion is explained by the formalism, in a manner similar to 
the WM duplication: it is just first person indeterminacy, not in a 
self-duplication, but in a self entanglement. 

Bruno




> But the interference at the screen depends only on things like the wavelength 
> of the light, the separation of the slits, and the distance between the slits 
> and the screen. If you refine this calculation by taking the finite width of 
> the slits into account, you convolute the interference pattern with the 
> diffraction pattern due to finite slit width. This is an elementary 
> calculation in physical optics, not even requiring quantum mechanics. But the 
> waves at the screen cannot be orthogonal, or else they would not interfere.
> 
> Bruce
> 
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