On Thursday, January 30, 2020 at 10:37:13 PM UTC-7, Brent wrote: > > > > On 1/30/2020 5:37 PM, Alan Grayson wrote: > > > > On Thursday, January 30, 2020 at 6:29:18 PM UTC-7, Alan Grayson wrote: >> >> >> >> On Thursday, January 30, 2020 at 5:09:56 PM UTC-7, Brent wrote: >>> >>> >>> >>> On 1/30/2020 12:45 PM, Alan Grayson wrote: >>> >>> >>> That's not it. I think the two observers, one in a galaxy far removed >>> and one here, would read the same CMBR "time", regardless of the distant >>> galaxy's speed of recession. But relativity says otherwise. This is what >>> puzzles me. AG >>> >>> >>> Ask yourself *when* do they read the same time. >>> >>> Brent >>> >> >> I don't know if this helps. Since the temperature of the CMBR is the same >> everywhere, at any time t, we can in principle determine if the two >> measurements are simultaneous or not. AG >> > > But regardless of simultaneity or not, there's no dilation of this clock! > (And AE doesn't say what a clock is.) What the hell is going on? AG > > > The clocks used in relativity examples are the whatever the most perfect > and stable clock in existence are (in this case cesium atom clocks). They > always measure proper time thru spacetime. The only reason that when > compared they seem to register different durations is because they traveled > different paths thru spacetime and these paths had different proper > length. "Time dilation" is not some function of the clock...it's a > function of the path the clock is measuring. Remember my odometer analogy? > > Brent >
Given that the temperature of the CMBR is the same for every location in space-time, it follows that time dilation is not a property of THIS clock. For this clock, which is NOT moving through space-time, paths through space-time are irrelevant. AG > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected] <javascript:>. > To view this discussion on the web visit > https://groups.google.com/d/msgid/everything-list/6e142235-e071-4c14-8eab-e06a09cb49d9%40googlegroups.com > > <https://groups.google.com/d/msgid/everything-list/6e142235-e071-4c14-8eab-e06a09cb49d9%40googlegroups.com?utm_medium=email&utm_source=footer> > . > > > -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion on the web visit https://groups.google.com/d/msgid/everything-list/3ae5dc47-8423-46fe-a9c0-63b3023a3672%40googlegroups.com.
