On Thu, May 5, 2022 at 5:27 AM smitra <smi...@zonnet.nl> wrote: > On 04-05-2022 01:49, Bruce Kellett wrote: > > On Tue, May 3, 2022 at 10:11 PM smitra <smi...@zonnet.nl> wrote: > > > What you are constructing is not the result of QM. > > > I think you are being confused by the presence of coefficients in the > > expansion of the original state: the a and b in > > > > |psi> = a|0> + b|1> > > > > The linearity of the Schrodinger equation means that the coefficients, > > a and b, play no part in the construction of the 2^N possible > > branches; you get the same set of 2^N branches whatever the values of > > a and b. Think of it this way. If a = sqrt(0.9) and b = sqrt(0.1), the > > Born rule probability for |0> is 90%, and the Born rule probability > > for |1> is 10%. But, by hypothesis, both outcomes occur with certainty > > on each trial. There is a conflict here. You cannot rationally have a > > 10% probability for something that is certain to happen. > > Of course you can. The lottery example shows that even in classical > physics you can imagine this happening. If a million copies of you are > made and one will win a lottery whole the rest won't then you have one > in a million chance of experiencing winning the lottery, even though > both outcomes of winning and losing will occur with certainty.
The trouble is that classically, a million copies of you cannot be made. The issue was that if the probability of an outcome is 10%, then it does not make sense to say that that outcome will certainly happen. Putting things off into other worlds does not make the logic work. If there is a copy of you for every ticket in the lottery, then you can say with certainty that one copy of you will have the winning ticket. But what sense does it make to say that your chance of winning is then one in a million? You can't have it both ways. If winning and not winning are both regarded as legitimate outcomes, then you are not certain to win, although you are certain to have an outcome. Whatever way you spin it, the same thing cannot both be certain and have a probability of 10% (or one in a million). Bruce -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to everything-list+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/everything-list/CAFxXSLQ4po5iHWyefMkk5-5AheiRTudkfkSJ2eXgfFAXX1ntTQ%40mail.gmail.com.
