# Re: It feels like Groundhog Day

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On 5/6/2022 4:35 AM, John Clark wrote:
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I'm changing the title because I think it's bad form for the title of a thread to contain the name of a list member, and because I really do feel like Bill Murray, we've been over this exact same ground over and over again almost verbatim. I'm (probably foolishly) going to do it one more time:
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Suppose you wanted to measure the gravitational constant G, how would you do it? You'd do it the same way Henry Cavendish did it 200 years ago, you'd use Newton's formula F= √(GM/r) where F is the gravitational force of attraction between 2 lead balls of equal mass if you chain one of the balls to the earth's surface and let the other one swing freely.
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??   F=GMM/r^2

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Now you'll need to determine the mass of the balls, and you can do that by noting how fast it accelerates when exposed to a known calibration force, for example a force provided by a precisely made coiled clockspring, but if the energy in the clockspring is half of what it was in Cavendish's day and the inertia of the lead ball is also half of what it was in Cavendish's day then the value of M you will write in your lab notebook will be the same as the value Cavendish wrote in his lab notebook. And the amount of time it takes for the freely swinging ball to hit the stationary ball that you write in your lab notebook will be the same as the time Cavendish found.  So the value of G that you write in your lab notebook will be the same value Cavendish wrote in his.
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So you're equating forces Kx=GMM/r^2 where K is the spring constant in Cavendish's experiment and x is the deflection.  Then you halve K and the M's.  Then G must double??
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Newton says the orbital velocity of a planet a distance r from the sun is  v= √ (GM/r) ,
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So the orbital velocity at the same radius would stay the same...which contrary to my idea that stellar aberration would change.  But now the number for G in books has changed.  But wait, there's more.  Distances are measured by time*SoL, and the speed of light, time is measured by cesium atoms energy levels.  So halving energy will double periods and wavelengths and the meter will double.  So if G->2G, M->M/2, and r->r/2  then v does increase by sqrt(2).
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Brent

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so if G is the same and M is the same (because the inertial and gravitational mass are always the same) then the orbital speed of a planet is the same, and the solar system would look the same. And because the gravitational acceleration on the surface of the earth g= GM/R^2 where M is the mass of the earth and R is the radius of the earth, g would still be 9.8 m/s, and force would still equal mass times acceleration.
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The one thing both Newton and Einstein agreed-upon is that gravitational mass and inertial mass are always exactly the same, and that's why Aristotle was wrong, something twice as heavy does not fall to the ground twice as fast; that's also why even physicist who are adamantly opposed to many worlds and love to badmouth it don't use the argument presented around here that the solar system would become unstable. Some around here are arguing in effect that Aristotle was right after all, an object twice as heavy would fall to the ground twice as fast and we should just ignore 2000 years worth of progress in physics. Unless somebody says something new that I haven't already responded to at least twice before (and at this point that seems unlikely) I'm done with this andGroundhog Day is finally over.
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John K Clark    See what's on my new list at Extropolis <https://groups.google.com/g/extropolis>
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