Le ven. 13 sept. 2024, 06:21, Alan Grayson <[email protected]> a
écrit :

>
>
> On Thursday, September 12, 2024 at 3:55:45 AM UTC-6 Quentin Anciaux wrote:
>
>
>
> Le jeu. 12 sept. 2024, 11:53, Alan Grayson <[email protected]> a écrit :
>
>
>
> On Thursday, September 12, 2024 at 2:40:56 AM UTC-6 Quentin Anciaux wrote:
>
> I just gave you a full proof that as long as the expansion is uniform and
> expansion rate > 0, then it follows objects will sooner or later recess
> from each other at speed > c.
>
>
> What was the justification for the geometric progression? I made no such
> assumption in my "proof".
>
>
> As explained multiple times and in the quote you made, expansion is
> uniform and happens at every point in space.
>
>
> What bothers me about your method is that you* assume* a geometric
> increase in the separation distance, when, IMO, that's the variable that
> must be calculated (which I did). So no matter how many times you affirm
> your proof as valid, I can't agree. AG
>


Why uniform expansion implies exponential growth

Uniform expansion does not necessarily mean that the sphere grows linearly.
In fact, uniform expansion implies that the proportion of growth remains
constant at every moment, which is the definition of exponential growth. If
the distance between the points increases proportionally to the current
distance, then we obtain exponential expansion, as seen in the example you
provided.

In this case, adding one extra point between each point at every step
illustrates the phenomenon of exponential expansion: at every moment, the
total distance increases in proportion to the existing distance.




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