On Fri, Oct 25, 2024 at 5:44 AM Alan Grayson <[email protected]> wrote:

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> On Friday, October 25, 2024 at 2:44:06 AM UTC-6 Brent Meeker wrote:
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> On 10/25/2024 1:36 AM, Alan Grayson wrote:
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> On Thursday, October 24, 2024 at 11:07:18 PM UTC-6 Brent Meeker wrote:
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> On 10/24/2024 5:46 PM, Alan Grayson wrote:
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> On Thursday, October 24, 2024 at 1:30:32 PM UTC-6 Brent Meeker wrote:
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> Here's  how a light-clock ticks in when in motion.  A light-clock is just
> two perfect mirrors a fixed distance apart with a photon bouncing back an
> forth between them.  It's a hypothetical ideal clock for which the effect
> of motion is easily visualized.
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> These are the spacetime diagrams of three identical light-clocks moving at
> *+*c relative to the blue one.
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> *Three clocks?  Black diagram? If only this was as clear as you claim. TY,
> AG*
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> *You can't handle more than two?  The left clock is black with a red
> photon.  Is that hard to comprehend?  Didn't they teach spacetime diagrams
> at your kindergarten?                 Brent *
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> *What makes you think you can teach? *
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> *That I have taught and my students came back for more.*
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> *I can handle dozens of clocks. I know what a spacetime diagram. It was
> taught in pre-school. Why did you introduce a red photon? A joke perhaps?
> How can a clock move at light speed? *
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> *None of the clocks in the diagram are moving at light speed.  The black
> one and the red one are moving at 0.5c as the label says.  What is it you
> don't understand about this diagram? Brent*
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> *One thing among several that I don't understand is how the LT is applied.
> For example, if we transform from one frame to another, say in E&M, IIUC we
> get what the fields will actually be measured by an observer in the target
> or primed frame. (I assume we're transferring from frame S to frame S').
> But when we use it to establish time dilation say, we don't get what's
> actually measured in the target frame, but rather how it appears from the
> pov of the source or unprimed frame. Presumably, that's why you say that
> after a LT, the internal situation in each transformed frame remains
> unchanged (or something to that effect). AG*
>

Can you give a concrete example? If you some coordinate-based facts in
frame S (source frame) and use the Lorentz transformation to get to frame
S' (target frame), the result should be exactly what is measured in the
target frame S' using their own system of rulers and clocks at rest
relative to themselves (with their own clocks synchronized by the Einstein
synchronization convention).

Jesse




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> *It's a real muddle. I think you meant well, but you don't have the
> maturity to contain your temper. Nonetheless, the photon clock gave me a
> good idea, which I just wrote about. AG *
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> Because the speed of light is invariant the photon paths are at unit slope
> inside all three clocks, so it is easily seen why the relative motion makes
> the clock seem slow although each clock is ticking at the same rate in it's
> own reference frame.  The red diagram is just the blue diagram Lorentz
> transformed as it would be seen in a frame moving the left at 0.5c, and the
> black diagram as it would be seen from a frame moving to the right.
>
> Brent
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>
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