On Tuesday, October 29, 2024 at 8:38:03 AM UTC-6 John Clark wrote:

On Tue, Oct 29, 2024 at 10:21 AM Alan Grayson <[email protected]> wrote:

*>> First of all Maxwell's Equations are consistent with Special and 
General Relativity but not with Quantum Mechanics, so all the charges that 
I'm talking about must be macroscopic.  A real baseball is electrically 
neutral but small (but not small by quantum mechanical standards) **parts 
of it **might be very slightly positive and other parts very slightly 
negative, and this creates a small electric dipole. So if you rotate the 
baseball those positive and negative parts will indeed radiate 
electromagnetic waves, and the positive and negative parts will only 
partially cancel out because they are in slightly different positions. So 
the spinning baseball will start to lose energy and slow down. However the 
radiated energy from rotating dipoles is proportional to the fourth power 
of angular frequency, so if you were rotating the baseball at just under 
the speed that would tear it apart, say about 2000 RPMs, that rotation is 
so slow that the effect would be far too tiny to be detectable with today's 
technology.*

*> I don't think this answers my question. The acceleration of a charged 
particle due to the Earth's rotation in the lab frame is not trivial, and 
should produce a measurable radiation, but AFAICT, it doesn't. AG *


*2000 RPMs is a trivially slow **angular frequency, and as I said the 
radiated power is proportional to the fourth power of the **angular 
frequency; so one revolution per 24 hours would be SUPER **trivially slow.*


I see. So the spinning baseball is sort-of a model for the spinning Earth. 
Without doing too much work, what's your best estimate for the time the 
Earth completely evaporates due to energy lost due to rotation? AG 


*John K Clark    See what's on my new list at  Extropolis 
<https://groups.google.com/g/extropolis>* 
4pt

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