On Friday, December 13, 2024 at 12:54:03 PM UTC-7 Jesse Mazer wrote:

On Fri, Dec 13, 2024 at 8:14 AM Alan Grayson <[email protected]> wrote:



On Friday, December 13, 2024 at 4:46:09 AM UTC-7 Alan Grayson wrote:

*I misstated the apparent paradox. Specifically, if we have car which in 
its rest frame fits in a garage, for sufficient v of the car, the garage 
length is Lorentz contracted, so the car will no longer fit. OTOH, from the 
pov of the garage frame, the length of the car is Lorentz contracted and 
will fit even better. (In my original formulation, I began with the car 
length greater than the garage length, in effect Lorentz contracting the 
garage length without first stating that in the rest frame, the car fits in 
the garage.) AG*


*I admit it; this is a pretty dumb question after all this discussion. But 
assuming the resolution involves disagreement between frames about 
simultaneity, what exactly IS the answer? Does the car fit or not, in which 
frames, under what constraints or conditions? TY, AG*


I think the general answer is that it fits in frames where the event "back 
of car passes front door of garage" happens earlier than the event "front 
of car hits back of garage (or passes back door of garage, if we imagine a 
covered bridge style garage)", and it does not fit in frames where the 
former event happens later than the latter event.


*Do you have this backwards? AG*
 

Which frames would fall into either category would depend on the specific 
values for relative velocity and rest lengths chosen in the problem, in a 
typical statement of the problem we are just asked to compare the car rest 
frame and the garage rest frame without worrying about other frames.

Jesse 


On Wednesday, December 4, 2024 at 2:06:41 PM UTC-7 Alan Grayson wrote:

In the case of a car whose rest length is greater than the length of the 
garage, from pov of the garage, the car *will fit inside* if its speed is 
sufficient fast due to length contraction of the car. But from the pov of 
the moving car, the length of garage will contract, as close to zero as one 
desires as its velocity approaches c, so the car *will NOT fit* *inside* 
the garage. Someone posted a link to an article which claimed, without 
proof, that this apparent contradiction can be resolved by the fact that 
simultaneity is frame dependent. I don't see how disagreements of 
simultaneity between frames solves this apparent paradox. AG

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